This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise
A person's lean body weight L is the amount he or she would weigh if all body fat were magically to disappear. One text gives the "equation that practitioners can use most feasibly in the field to predict lean body weight in young adult males." The equation is found below.
L = 98.42 + 1.08W − 4.14A
Here L is lean body weight in pounds, W is weight in pounds, and A is abdominal circumference in inches. Find the approximate lean body weight of a young adult male who weighs 181 pounds and has an abdominal circumference of 41 inches. What is the weight of his body fat? What is his body fat percent?
Step 1
To get the lean body weight of a young adult male who weighs 181 pounds and has an abdominal circumference of 41 inches we use W =
and A =

the answer is c hope it

step-by-step explanation:

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°

it is x equals 3   plese mark me really need it

step-by-step explanation:

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.