Please help :( Given that sin(2x) +cos(2x)=1+sin(x) and that sin (x) does not equal to 0, show that 2(cosx-sinx)=1​

steps below

Step-by-step explanation:

sin(2x) +cos(2x)=1+sin(x)

2sinxcosx + (1 - 2sin²x) = 1 + sinx

(2sinxcosx  - 2sin²x) +1 = 1 + sinx

2sinx(cosx-sinx) + 1 = 1 + sinx  .. minus 1 both side

2sinx(cosx-sinx) = sinx    ... sinx ≠ 0, divide sinx both side

2(cosx-sinx) = 1

answer: a and b

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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