How to do this question??

h(2)= - 12

Step-by-step explanation:

What that means is: calculate the y-value when t=2. Where you see t, substitute 2 in the equation. y= - (2)^2 - 2(2) - 4

The answer is - 12

-12

Step-by-step explanation:

qu.   h(t) = -t^2 - 2t - 4

where h = 2

= h(t) = (-t^2)- (2^t)- (4)

= h(2) = (-2^2) - (2^2) - (4)

         = (-4) - (4) - (4)

          = -12

The way the brackets are done will help you when its mixed numbers and positives as the first polynomial if negative must be kept in bracket.

4th option is correct xy=-10

if this was to u plzz mark me the brainliest

answer is 12345678900987654321234567890987654321

step-by-step explanation: