What is the equation of a line perpendicular to y=1/4x+2 that passes through the point (0,1)

y = -4x + 1 or y = 1 - 4x

Step-by-step explanation:

First, we have to find the slope of the perpendicular. The slope of the line perpendicular to the other is the reciprocal and opposite value of the other line's slope.

This means that the slope perpendicular to y = 1/4x + 2 is -4, or -4/1.

Now we need to find the y-intercept, to do that we will use the equation y = mx + b. m = slope, b = y-intercept.

Plug in the values.

1 = -4(0) + b

Simplify.

1 = 0 + b

1 = b

Our y-intercept is 1.

Now we can form the slope-intercept equation for the line perpendicular to y = 1/4x + 2 that passes through the point (0, 1).

y = -4x + 1

(c, 0) i might be wrong so don't put full faith on my answer

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph