Mathematics, 11.09.2021 01:40 mimi8734
A small object begins a free‑fall from a height of 21.0 m.
After 1.20 s, a second small object is launched vertically upward from the ground with an initial velocity of 34.0 m/s.
At what height ℎ
above the ground will the two objects first meet?
Answers: 2
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Determine the fraction of total interest owed. after the fourth month of a 12-month loan: the numerator is: {(n + ) + (n + ) + (n + ) + (n + )} = , and the denominator is: {(n) + (n + 1) + + (n + )} = . therefore, the fraction is numerator/denominator (to the nearest tenth) =
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A small object begins a free‑fall from a height of 21.0 m.
After 1.20 s, a second small object is...
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