Let triangle ABC square at A(AB < AC) . Let D and E be the midpoints of the lines BC and AC respectively. Draw DF perp AB at F. Let O be the intersection of AD and FE. a. What is the quadrilateral AFDE? Prove. b. Let I be the point symmetrical to D about AC. Prove that DI is the bisector of angle ADC. C. Draw AH as altitude of triangle ABC Prove angle FHE is right angle

i am sure it will be 90 degrees.

step-by-step explanation:

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

part a: 1.08

part b: 27.59

c. 1,233 miles