a water tank can be filled completely in 15 hours. if the tank is filled for 5×1÷2hours and left .what part of the tank is remained to be filled please answer fast i will give you as brainliest fast plz ​

Let Volume of Tank be V

pipe A can fill the tank  

5

V

​

 in 1 Hour

pipe B can fill the tank  

8

V

​

 in 1 Hour

Drainage Hole can empty the tank  

20

V

​

 in 1 Hour

⇒  

5

V

​

+  

8

V

​

−  

20

V

​

=  

T

V

​

where  

T

V

​

 is the Volume filled when 2 pipes and 1 hole is opened, in 1 Hour

⇒  

5

1

​

+  

8

1

​

−  

20

1

​

=  

T

1

​

solving we get T=  

11

40

​

hrs

Step-by-step explanation:

A tank can be filled in 9 hours by one pipe, 12 hours by a second pipe and can be drained when full by a third pipe in 15 hours.

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true