One movie is 120 minutes long. Another is 100 minutes long. If both movies are started at 12 p. m., at what time will they start together again?

3:40 pm

Step-by-step explanation:

120 is 2 hours and 100 is 1 and 40 minutes

Given:

Time length of first movie = 120 min

time length of second movie = 100 min

start time = 12 pm

To find:

What time will they start together again

Steps:

for this question we have to find LCM of both of them,

120 = 2 * 2 * 2 * 3 * 5

100 = 2 * 2 * 5 * 5

LCM = 2 * 2 * 2 * 3 * 5 * 5

LCM = 4 * 2 * 3 * 5 * 5

LCM = 8 * 3 * 5 * 5

LCM = 24 * 5 * 5

LCM = 120 * 5

LCM = 600 min

600 min = 600/60 hr

              = 10 hours

Therefore, they will start again at 10 o'clock

Happy to help :)

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

positive

step-by-step explanation:

the quadrant is facing upwards