Hi. I'm an 11 IB student and our current topic is "Geometric Sequences." I can't understand how to do the following question. "The numbers 3a + 1, a + 2, and a - 4 are three consecutive terms of a geometric sequence. Find the two possible values of the common ratio."

I would really appreciate it if someone could explain how to solve this problem.
Thanks in advance.

Period is the time it takes for one “cycle” to complete. in the parent sine function, period is 2*pi since sin(0) = 0, sin(pi/2) = 1, sin(pi) = 0, sin(3pi/2) = -1, and sin(2pi) = 0. at that point, the sequence repeats itself. i’m not sure if your graph is similar to the sine function since you didn’t provide a picture, but you can find the period by looking at a graph.

How many is in each case if there is 12 in each case it would be 40