A line passes through the point (1, - 6) and has a slope of 8. Write an equation in slope-intercept form for this line.

Step-by-step explanation:

We are asked to find the equation of a line in slope-intercept form. We are given a point and a slope, so we can use the point-slope formula.

In this formula, m is the slope and (x₁, y₁) is the point the line passes through. The slope of the line is 8 and it passes through the point (1, -6). Therefore,

Substitute these values into the formula.

Remember that 2 back to back subtraction signs are the same as an addition sign.

The line must be in slope-intercept form or y=mx+b (m is the slope and b is the y-intercept. We must isolate the variable y on one side of the equation. First, distribute on the right side of the equation. Multiply each term inside the parentheses by 8.

6 is being added to y. The inverse operation of addition is subtraction, so we subtract 6 from both sides of the equation.

The equation of the line in slope-intercept form is y=8x-14. The slope is 8 and the y-intercept is -14.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)