2x2-xy-y2=15 find dy ait (2,5) doc​

1/4.

Step-by-step explanation:

Using implicit differentiation:

2x^2 - xy - y^2 = 15

4x - (x.dy/dx +1.y) - 2y.dy/dx = 0

4x - x.dy/dx - y - 2y.dy/dx =0

-2y.dy/dx - x. dy/dx = y - 4x

dy/dx = (y - 4x)/(-2y - x).

So at the point (2, 5):

dy/dx = (5 - 4(2)) / (-2(5) - 2)

= -3/-12

= 1/4.

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v