Write the equation of the line that passes
through (4,-5) and is parallel to y=-2x-4.

y=-2x+3

Step-by-step explanation:

Hi there!

We are given the point (4, -5) and we want to write the equation of the line that passes through that point and is parallel to the line y= -2x-4

Parallel lines have the same slope, but different y intercepts.

So let's find the slope of the line y=-2x-4

The line is written in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept

As -2 is in the place of where m, the slope is, then -2 is the slope of the line. It is also the slope of the line parallel to it.

So let's write the equation of this new line in slope-intercept form. So far, we have:

y=-2x+b

So we need to find b

As the equation passes through the point (4, -5), we can substitute its values into the equation to solve for b

So substitute 4 as x and -5 as y in y=-2x+b

-5=-2(4)+b

Multiply

-5=-8+b

Add 8 to both sides

3=b

Substitute 3 as b in the equation

y=-2x+3

Hope this helps!

the answer is d. 75%