8. A Caribbean resort has a nightly limbo contest on the beach. Participants must be less than 64 inches tall. The distribution of heights of adult American
men is approximately normal with mean 69 inches and standard deviation
2.5 inches.
a. What percent of adult American males could enter this contest?
b. How tall would a man have to be for his height to be in the top 15%?
9. Visitors to the Royal Ronal con

21 i watched a 3 hr vid explaining it

step-by-step explanation:

du what else would it be

brainliest

answer: 5 17/33 % (to the tenth)

step-by-step explanation:

he guessed: 34.5 pounds

actual weight is 32.7

there for he is off:

34.5 -32.7 = 1.8

32.7 is the 100%

1.8 represents %? of 32.7

therefore:

32.7   - 100%

1.8     -     x%

x= 1.8*100%/32.7% = 18*100%/327%

x=1800%/327%   = (5 165/327)%

to the tenth:

5 17/33 %

if you would like with a question it is easy to get an answer by including some or multi choice options

step-by-step explanation: