Prove that, (3-4sin2A)(sec2A-4tan2A)=(3-tan2A)( 1-4sin2A)​

(3-4sin^2x) (1-3tan^2x)

= (3-4sin^2x) * (cos^2x-3sin^2x)/cos^2x

= (3-4sin^2x)/cos^2x * (cos^2x-3sin^2x)

= (3sec^2x-4tan^2x)(cos^2x-3sin^2x)

= (3+3tan^2x-4tan^2x)(cos^2x-3sin^2x)

= (3-tan^2x)(cos^2x-3sin^2x)

= (3-tan^2x)(cos^2x-3+3cos^2x)

= (3-tan^2x)(4cos^2x-3)

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