Mathematics, 02.09.2021 23:20 elijahjacksonrp6z2o7
Explain what it means to say that lim x β 9β f(x) = 3 and lim x β 9+ f(x) = 5. As x approaches 9, f(x) approaches 5, but f(9) = 3. As x approaches 9 from the right, f(x) approaches 3. As x approaches 9 from the left, f(x) approaches 5. As x approaches 9, f(x) approaches 3, but f(9) = 5. As x approaches 9 from the left, f(x) approaches 3. As x approaches 9 from the right, f(x) approaches 5. In this situation is it possible that lim x β 9 f(x) exists? Explain. Yes, f(x) could have a hole at (9, 3) and be defined such that f(9) = 5. Yes, f(x) could have a hole at (9, 5) and be defined such that f(9) = 3. Yes, if f(x) has a vertical asymptote at x = 9, it can be defined such that lim xβ9β f(x) = 3, lim xβ9+ f(x) = 5, and lim xβ9 f(x) exists. No, lim xβ9 f(x) cannot exist if lim xβ9β f(x) β lim xβ9+ f(x).
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Explain what it means to say that lim x β 9β f(x) = 3 and lim x β 9+ f(x) = 5. As x approaches 9, f(...
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