The first side of a triangle is cm long. The second side is twice as long as the first. The third side is 5 cm longer than the second side. The perimeter of the triangle is
1 metre.

write an equation to show this.
solve the equation.
find the length of the longest side of the triangle.

First side is 19, second side is 38 and third side, the longest is 43.

Step-by-step explanation:

Let's call the first side a.  

The second side, being twice as long as the first, is 2a.

The third side is 2a+5.

The equation is:

a+2a+2a+5=100, since 1 metre is 100 centimetre.

5a+5=100

5a=95

a=19

First side is 19, second side is 38 and third side, the longest is 43.

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step-by-step explanation:

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.