![m< xyz=\frac{1}{2}(a-b)](/tex.php?f=m< xyz=\frac{1}{2}(a-b))
![m< xoy=b](/tex.php?f=m< xoy=b)
step-by-step explanation :
we know that
the measurement of the outer angle is the semi-difference of the arcs which comprises
in this problem
m< xzy is the outer angle
![m< xyz=\frac{1}{2}(mayor\ arc\ xy-minor\ arc\ xy)](/tex.php?f=m< xyz=\frac{1}{2}(mayor\ arc\ xy-minor\ arc\ xy))
substitute the values
![m< xyz=\frac{1}{2}(a-b)](/tex.php?f=m< xyz=\frac{1}{2}(a-b))
the measure of angle xoy is equal to
> by central angle
substitute the value
![m< xoy=b](/tex.php?f=m< xoy=b)
![Which equation is correct regarding the diagram of circle o? a) m∠xzy = (a + b)b) m∠xzy = (a – b)c)](/tpl/images/02/04/WALcUfYk0pH3PG7J.jpg)