4. What is the equation of a line parallel to y = 3x + 6 that passes through (-4, 1)?

y = 3x -1

Step-by-step explanation:

always remember the formula y = mx + c

m is the gradient and c is the y intercept

you already know the gradient to be 3 since the line is parallel. so, let's just imagine you are standing on the point -4, 1

for every 1 step you move on the x axis, your y value will increase by 3

thus your y intercept will be -4 + (1x3) which is - 1

by substituting the values you have just gotten, you will get your answer

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)