suppose the velocity of a particle traveling along the x-axis is given by v(t)= 3t^2+8t+15 m/s at time t seconds. The particle is initially located 5 meters left of the origin. How far does the particle travel from t=2 seconds to t=3 seconds? After 3 seconds, where is the particle with respect to the origin?

Step-by-step explanation:

1) How far does the particle travel from t=2 seconds to t=3 seconds?

2)

After 3 seconds, where is the particle with respect to the origin?

108-5=103 (m)

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.