Point J is between H and K on HK. Use the given information to write an equation in terms of x. Solve the equation. Then find HJ and JK.
HJ = 2x
JK = 3x
KH = 25

HJ = 5x - 3
JK = x - 9
KH = 5x

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

Show your workcan a right triangle have this sides? *how to prove it without using the pythagorean theorema*

If cos(2x) = tan^2(y), show that cos(2y) = tan^2(x).