What is the vertex of the parabola of the parabola that is formed from the function?

vertex = (2, - 1 )

Step-by-step explanation:

Given a parabola in standard form

f(x) = ax² + bx + c ( a ≠ 0 ) , then

The x- coordinate of the vertex is

= -

f(x) = x² - 4x + 3 ← is in standard form

with a = 1, b = - 4 , then

= - = 2

Substitute x = 2 into f(x) for corresponding y- coordinate

f(2) = 2² - 4(2) + 3 = 4 - 8 + 3 = - 1

vertex = (2, - 1 )

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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