G (x) = -x^2-6x+2. Find g(0), g (1), and g (-3)

g(0)=2, g(1)=-3 ,g(-3) =29

Step-by-step explanation:

x²-6x+2

g(0) = 0²-6(0)+2

= 0-0+2

= 2

g(1) =1²-6(1) +2

=1-6+2

=-3

g(-3) =(-3)²-6(-3) +2

=9+18+2

=29

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer