Given the definitions of f(x)f(x) and g(x)g(x) below, find the value of (f\circ g)(-2).(f∘g)(−2). f(x)=
f(x)=
\,\,3x^2+6x+11
3x
2
+6x+11
g(x)=
g(x)=
\,\,2x+7
2x+7

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

answer: group b.

step-by-step explanation: