Mathematics, 25.08.2021 16:10 chalowiee1570
Show that the tangent at the point P, with parameter t, on the curve x=3t, y=2t^3 has equation y=tx - t^3.Prove that this tangent will cut the curve again at the point Q with coordinates (3t^2/4,t^3/4).Find the coordinates of the possible positions of P if the tangent to the curve at P is the normal to the curve at Q​
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Need match the functions with correct transformation. f(x) = -3x f(x) = |x-1|+3 f(x) = √(x+3) 1/2x² f(x) = (x+1)²-3 4|x| 1. compress by a factor of 1/2 2. stretch by a factor of 4 3. shift to the left 3 4. shift to the left 1 5. shift up 3 6. reflection
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Show that the tangent at the point P, with parameter t, on the curve x=3t, y=2t^3 has equation y=tx...
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