Find the Quotient and Remainder. 5x^3 - 6x^2 + x + 7 divided by x^2

Step-by-step explanation:

Solution

According to remainder theorem, when f(x) is divided by (x+2), Remainder =f(−2)

f(x)=5x3+2x2−6x+12

f(−2)=5(−2)3+2(−2)2−6(−2)+12

=5×−8+2×4+12+12

=−40+32=−8

∴ Remainder=−8

solution

Quotient=5x-6

remainder=1/X+7/x^2. Answer

Step-by-step explanation:

(5x^3-6x^2+X+7)/x^2

5x-6+1/X+7/X^2

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10