A chemical company sells a specialized industrial lubricant in 20 liter containers. A random sample of the latest production lot shows the contents of 10 containers to be 20.3, 19.91, 19.98, 19.69, 19.54, 20.51, 20.36, 20.46, 19.68, and 20.56 liters. Find the standard deviation of the sampled containers’ contents. A. σ=0.36

B. σ=0.55

C. σ=0.53

D. σ=0.42

the answer for this question is 38

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

a

step-by-step explanation:

$2416.6

step-by-step explanation:

per hour = $ 25

total work time = 35

commission = 15%

total she has to make = $ 4,500

let she sold x dollar products

so her commission will be 15 % of x

now

total = weekly basic pay + commission

4500= (25*35) + 15 % of x

4500=875 + * x

4500-875 =   * x

3625= * x

multiplying wwith 100 on both sides gives

36250 = 15 x

now

x =  

x= $2416.6