Weve used two algebraic methods for solving a system of
Mathematics, 23.08.2021 01:00 gokusupersaiyan12345
K+a = 500
3k + 100 = 3,600
Weve used two algebraic methods for solving a system of
equations--substitution and elimination. We can use either of
these two methods and get the same solution. Choose
whichever method is easier for solving a particular system.
When graphing a system of equations, the intersection point of
the two lines represents the system's solution. Not all systems of
equations have a single solution. Some systems have no
solution, and some have an infinite number of solutions. You'll
recall that we came across these same possibilities earlier while
solving single linear equations.
So far in this lesson, we've worked with systems of equations
with one solution. Now, let's explore systems with no solution,
and systems with Infinite solutions.
1400
300 3x + 10y = 3,600
800
number of kids
700
600
500
400
300
(300,200)
200
100
wy500
100 200 300 100 500 600 700 800 900 1000 1.100
number of adults
Answers: 3
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Peter applied to an accounting firm and a consulting firm. he knows that 30% of similarly qualified applicants receive job offers from the accounting firm, while only 20% of similarly qualified applicants receive job offers from the consulting firm. assume that receiving an offer from one firm is independent of receiving an offer from the other. what is the probability that both firms offer peter a job?
Answers: 1
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Find the magnitude, correct to two decimal places, made by each of the following with positive direction of the x axis a) y= x the answer is 45° but i don’t know how
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Campus rentals rents 2 and 3 bedrooms apartments for $700 ans $900 a month respectively. last month they had six vacant apartments and reported $4600 in lost rent. how many of each type of apartment were vacant?
Answers: 1
K+a = 500
3k + 100 = 3,600
Weve used two algebraic methods for solving a system of
Weve used two algebraic methods for solving a system of
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