Solve the equation 3 cos 2 theta + sin theta = 1 for values of theta from 0 degrees to 180 degrees​

Step-by-step explanation:

Recall that

so we can write our original equation as

or

Let so our equation becomes

which gives us two roots: and .

This is equivalent to and

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

b, i believe, but not sure.