If p is true and q is false, the p->q is
true.
never
always
sometimes

never

Step-by-step explanation:

p->q means if p is true, then q must also be true

but since q is false, p->q is never true

Never

Explanation:

The notation p -> q refers to a conditional statement.

Conditionals are only false when the first part (p) is true while the second part (q) is false. In other words, the template true --> false ultimately leads to a false statement. Otherwise, the entire thing is true.

In our case, we have something that fits the "true -> false" template, so that's why p -> q is never true when p = true and q = false.

give more details

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240