"Write two equations: one parallel, one perpendicular to (5,-2) y= 1/5x-3 Write in the form y=mx±b, y=mx±b (first the parallel, then the perpendicular)"

For parallel:

gradient is 1/5

consider (5, -2):

For perpendicular:

gradient, m1:

gradient = -5

Parallel:

Perpendicular:

Step-by-step explanation:

Hi there!

What we must know:

Finding the Parallel Line

Given this equation, we can identify that its slope (m) is . Because parallel lines always have the same slope, the slope of the line we're currently solving for would be as well. Plug this into :

Now, to find the y-intercept, plug in the given point (5,-2) and solve for b:

Therefore, the y-intercept is -3. Plug this back into :

Our final equation is .

Finding the Perpendicular Line

Again, the slope of this line is . The slopes of perpendicular lines are negative reciprocals, so the slope of the line we're solving for would be -5. Plug this into :

To find the y-intercept, plug in the point (5,-2) and solve for b:

Therefore, the y-intercept is 23. Plug this back into :

Our final equation is .

I hope this helps!

a

explanation:

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)