Sidney has two different acid solutions: A is a 50% acid solution, and B is an 80% acid solution. Determine how much of each solution he needs to
create 200 ml of a 68% solution.

80 ml of the first solution and 120 ml of the second solution

Step-by-step explanation:

Let the first solution weigh x ml, let the second solution weigh 200-x ml.

The amount of acid in the first solution is x/100*50=0.5x

The amount of acid in the second one is (200-x)/100*80= 160-0.8x

The quantity of acid in the desired mixture is 200/100*68= 136

0.5x+160-0.8x= 136

0.3x=24

x=80ml of the first solution are needed

200-80=120ml - of the second solution are needed

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according to egenuity the answer is

step-by-step explanation:

d. 344.22