What is the distance between points (4,0) and (-2,-3)

Hi! I'm happy to help!

To solve this equation, we need to find how much distance is between the y coordinates, how much distance is between the x coordinates, and then use the Pythagorean Theorem.

Let's start with finding the distance between the x coordinates. The first x coordinate is 4, and the second is -2. This means that the distance in x is 6.

Next, we need to find how much distance is between the y coordinates. The first y point is at the y coordinate 0, and the second is at the y coordinate -3. This means that the distance in y is 3.

Now we use the Pythagorean Theorem, which says that a²+b²=c²

A and b refer legs of a right triangle, and c refers to the hypotenuse (longest side) of the right triangle. Imagine the two points on a line, the direct distance is the c, and the y and x movements alone are a and b.

Let's say x is a, and y is b. Let's insert our values:

6²+3²=c²

36+9=c²

45=c²

To find c, we need to find the square root of 45

√45

6.708203...

Rounds to about 6.7 in tenths.

So, the distance between those two points is about 6.7.

I hope this was helpful, keep learning! :D

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)