which of the following are ordered pairs for the given function f(x)=1+x.? (1,2) (3,3) (0,2) (1,0) (0,1)

no,  

(

1

,

0

)

is not an ordered pair of the function  

f

(

x

)

=

1

+

x

.

Step-by-step explanation:

Ordered pairs are usually written in the form  

(

x

,

y

)

by tradition.

so usingthe function,

f

(

x

)

=

1

+

x

we can rewrite it as,

y

=

1

+

x

any pair of x and y that satisfy this equation are solutions to the equation.

so subbing in  

(

1

,

0

)

,

0

=

1

+

(

1

)

0

=

2

which is not true so the point does not make the function true.

It might be easier to see graphically,

graph{1+x [-10, 10, -5, 5]}

any combination of x and y on this line make the equation true and as such are an ordered pair of the function.

Step-by-step explanation:

a negative exponent is translated as follows:

so, we have

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3