The slot size limit for Fish A is from 28 to 32 inches. The minimum size limit for Fish B is 11 inches. Write the ranges of Fish A and Fish B in interval notation and in set-builder notation. Does the range for the Fish B seem reasonable? Explain.

Notations are used to specify the range of a function. The range of fish A is [28,32] while the range of fish B is [11,infinity).

Also, the range of fish B is not reasonable.

For fish A, we have:

For Fish B, we have:

For fish A, the minimum and the maximum are inclusive. So, the range is:

This gives:

For fish B, the minimum is known (and inclusive). The maximum is not known, so we represent the maximum with infinity.

So, the range is:

The range of fish B is not reasonable because there is a limit to the size of fish a slot can take.

Read more about interval notation at:

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation:

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.