A particle moves along a straight line and its position at time t is given by s(t)=2t3−18t2+48t where s is measured in feet and t in seconds. A) Find the velocity (in ft/sec) of the particle at time t=0.
B) The particle stops moving (i. e. is in a rest) twice, once when t=A and again when t=B where A C) What is the position of the particle at time 12?
D) Finally, what is the total distance the particle travels between time 0 and time 12?

answer: 72: 111

step-by-step explanation:

the answer is a.

135 and 80

step-by-step explanation:

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation:

step-by-step explanation:

oh the deck is the size of my dic k so about 320 inches hope u get my dic k as the answer