Find x if 2 {x}^2- 3 {x} + 1 >0, where {.} denotes the fractional part in [- 1, 1]

Step-by-step explanation:

−1,

2

−1

]∪[0,

2

1

]∪{1}

For f to be defined 2{x}

2

−3{x}+1≥0

({x}−1)(2{x}−1)≥0

⇒{x}∈(−∞,

2

1

)∪[1,∞)

But we know, {x}∈[0,1)

Thus {x}∈[0,

2

1

)→(1)

Also given that x∈[−1,1]

Hence required domain is [−1,−

2

1

]∪[0,

2

1

],∪{1}

Note {−x}=1−{x}

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

the answer is 62.8 cubic units