A mother is presently four times as old as her daughter if the sum of their ages 6 years ago was 48 find their present ages i need this answer with explanation
ASAP pl

Daughter is 12 and mother is 48.

Step-by-step explanation:

Let the daughters age be x years now then the mothers age is 4x.

6 years ago the daughter was x-6 years  and the mother was 4x - 6.

So we have the equation:

x - 6 + 4x - 6 = 48

5x - 12 = 48

5x = 60

x = 12

So the daughter is 12 and the mother is 4*12 = 48.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)