Find k such that 16x2 – 8 /3x+k=0 has a repeated real solution.

k =

Step-by-step explanation:

Using the discriminant

Δ = b² - 4ac

For a repeated real solution then

b² - 4ac = 0

Given

16x² - x + k = 0

with a = 16, b = - , c = k

(- )² - ( 4 × 16 × k) = 0

- 64k = 0 ( subtract from both sides )

- 64k = - ( divide both sides by - 64 )

k =

-8

step-by-step explanation:

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.