An Olympic diver jumps off of a platform that is 10 meters high. The diver goes 2 meters underwater after a dive. How far is it from the starting point at the top of the platform to the depth under water?

12 meters far.

Step-by-step explanation:

The question translates to 10+2. The word problem states that the height of the platform is 10 meters. That means we can say that he'd have already traveled 10 meters down when he dived. And the problem also states that the diver goes two meters under the water, meaning that he had traveled 2 meters, in addition to the 10 meters. And so, we add the 10 and 2 to get 12 meters in total.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2