The expression 2x³+ ax² + bx-30 is divisible by x + 2 and leaves a remainder of -35 when divided by 2x-1. Find the values of the constants a and b. I will give brainliest to correct answer

a= 25/3

b= 19/3

Step-by-step explanation:

step by step expl. in pic

a = 5, b = - 13

Step-by-step explanation:

The Remainder theorem states that the remainder when f(x) is divided by (x - a) is equal to f(a)

Thus the remainder for division by (x + 2) is zero , then by substituting x = - 2 into the expression.

2(- 2)³ + a(- 2)² + b(- 2) - 30 = 0

2(- 8) + 4a - 2b - 30 = 0

- 16 + 4a - 2b - 30 = 0

- 46 + 4a - 2b = 0 ( add 46 to both sides )

4a - 2b = 46 → (1)

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Similarly when f(x) is divided by (cx - a) the remainder is f( )

The remainder on dividing by (2x - 1) is - 35, then by substituting x =

2( )³ + a( )² + b - 30 = - 35

2( ) + a + b - 30 = - 35 ( add 30 to both sides )

+ a + b = - 5 ( multiply through by 4 to clear the fractions )

1 + a + 2b = - 20 ( subtract 1 from both sides )

a + 2b = - 21 → (2)

Solve (1) and (2) simultaneously )

Add (1) and (2) term by term to eliminate b

5a = 25 ( divide both sides by 5 )

a = 5

Substitute a = 5 into (2)

5 + 2b = - 21 ( subtract 5 from both sides )

2b = - 26 ( divide both sides by 2 )

b = - 13

think about it deeply and passionately about this property

i am sorry