How do i express x^2-3x into the form of (x-m)^2+n. I will give brainliest to correct answer

Step-by-step explanation:

let's simply do the multiplications and then compare with the original.

(x-m)² + n

right ?

or is it

let's go for the first.

x² - 2mx + m² + n = x² - 3x

-2mx + m² + n = -3x

fun there we see two things :

-2m = -3

m = 3/2

and

m² + n = 0

(3/2)² = -n

9/4 = -n

n = -9/4

so our transformed expression looks like

(x - 3/2)² - 9/4

it's

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180