Halla el mínimo común múltiplo de los siguientes pares de números. a. 32 y 68
b. 52 76
c. 84 y 95
d. 105 y 210
e. 380 y 420
f. 590 y 711
g. 320 y 640
h. 420 y 1.260
i. 140, 325 y 490
j. 725, 980 y 1.400

Es para hoy necesito ayuda

I’m a smart person so that’s why i think it was 6

45 is the only number in both sets

Ok here we go ..there are plenty of ways to solve such math problems but we will go for the smartest and easiest ..5x+2y=7  -2x+6y=9we rearrange them into the following ..by multiplying the 1st equation by 2 it becomes 10x + 4y = 14we rearrange it and so it becomes 10x = 14 - 4yas for the second equation we multiply it by 5 and rearrange it so it becomes as to the following ..-10x + 30y = 45rearranging so 10x = 30y -45now 10x equals both 14 - 4y and 30y -45so   14 - 4y = 30y -4531 = 26yy= 31/26 = 1.19 or around 1.2so by now we can calculate x easily as  -2x+6y=9so 2x = 6y -9 = 6 * 31/26 - 9 = -1.84  then x = - 0.92 or around -0.9best luck!