Suppose h(x)=3x-2 and j(x) = ax +b. Find a relationship between a and b such that h(j(x)) = j(h(x)) Probably a simple answer, but I'm completely lost at what I'm being asked here.

Step-by-step explanation:

We can use the definition of inverse functions. Recall that if two functions, f and g are inverses, then:

So, we can let j be the inverse function of h.

Function h is given by:

Find its inverse. Flip variables:

Solve for y. Add:

Hence:

Therefore, a = 1/3 and b = 2/3.

We can verify our solution:

And:

step-by-step explanation:

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.