Which values are solutions of the quadratic equation 0 = (x + 3)2 – 4? Check all that apply. –5 –4 –3 –1 3 5

hi

(x+3)^2 -4 = ( (x+3) +2) ( (x+3)-2 )

= ( x+5) (x +1)

so

solutions are : x+5=0 so x=-5

x+1= 0. so x= -1

solution are -5 +and -1

the answer to this question is 3/19

step-by-step explanation: