Chocolate bars come in packs of 8 and graham crackers come in packs of 12.  What is the smallest number of chocolate bars and graham crackers we would need to buy so we don't have any left over?  ​

3 chocolate bars, and 2 graham crackers

Someone forgot the marshmallows :P

Step-by-step explanation:

Chocolate bars = 8 pack

Graham Crackers = 12pack

To have no crackers or chocolate left over, we need to find LCM

Factors of 8:

8, 16, 24, 32, 40, 48, 56, 72

Factors of 12:

12, 24, 36, 48, 60, 72

The smallest LCM is 24

Chocolate bars:

24/8 = 3

Graham Crackers:

24/12 = 2

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

3 packs of chocolate and 2 packs of crackers

Step-by-step explanation:

the lowest common multiple of 8 and 12 is 24. We can determine this by prime factorization:

Prime factors of 8: 2 x 2 x 2

Prime factors of 12: 2 x 2 x 3

multipyling the bottom rungs of our factor tree we get: 2 x 2 x 2 x 3 = 24.

If you need me to draw the factor tree, just ask.

multiply each one by 3.14

step-by-step explanation:

a 90 degree rotation across the the origin followed by a reflection across the x-axis.

step-by-step explanation: