For each pair of equations, write the letter of the equation that expresses an equal value. 1. a. L = 1 dm3 b. 1 L = 1 cm3
2. a. 1 mL = 1 cm3 b. 1 cm3 = 1 L
3. a. 0°C = –273 K b. 0 K = −273°C
4. a. 1 kg = 100 g b. 1,000 g = 1 kg
5. a. 400 cm = 4.0 m b. 400 cm = 0.40 m
6. a. 1 dm = 10 m b. 1 dm = 0.10 m
7. a. 100°C = 373 K b. 373 K = 10°C

We must understand that certain standards has been layed down for the conversions of measuring units. A summary of such standards are discussed below:

1. Option A. 1 L = 1 dm³

2. Option A. 1 mL = 1 cm³

3. Option B. 0 K = −273 °C

4. Option B. 1000 g = 1 kg

5. Option A. 400 cm = 4.0 m

6. Option B. 1 dm = 0.10 m

7. Option A. 100°C = 373 K

1. Option A. 1 L = 1 dm³

Option B. 1 L = 1 cm³

From standard measurement,

1 L = 1 dm³

1 L = 1000 cm³

From the measuring standard, we can see that 1 L  ≠ 1 cm³.

Hence, option A gives the correct answer.

2. Option A. 1 mL = 1 cm³

Option B. 1 cm³ = 1 L

Hence, option A gives the correct answer.

From standard measurement,

1 mL = 1 cm³

1000 cm³ = 1 L

Thus, option A gives the correct answer.

3. Option A. 0°C = –273 K

Option B. 0 K = −273 °C

Recall:

T (K) = T(°C) + 273

T (K) = Temperature in Kelvin

T(°C) = Temperature in decree celcius

Next, we shall convert 0°C to K

T(°C) = 0°C

T (K) = T(°C) + 273

T (K) = 0 + 273

T (K) = 273 K

Thus, 0°C is equivalent to 273 K

Next, we shall convert 0 K to °C

T(K) = 0

T (K) = T(°C) + 273

0 = T(°C) + 273

Collect like terms

0 – 273 = T(°C)

T(°C) = –273°C

Thus, 0 K is equivalent to –273°C

Therefore, option B gives the correct answer.

4. Option A. 1 kg = 100 g

Option B. 1000 g = 1 kg

From standard measurement,

1 Kg = 1000 g

1000 g = 1 Kg

Hence, Option B gives the right answer

5. Option A. 400 cm = 4.0 m

Option B. 400 cm = 0.40 m

From standard measurement,

100 cm = 1 m

Converting 400 cm to m, we have:

Thus, option A gives the correct answer.

6. Option A. 1 dm = 10 m

Option B. 1 dm = 0.10 m

From standard measurement,

10 dm = 1 m

Thus,

Therefore, option B gives the correct answer.

7. Option A. 100°C = 373 K

Option B. 373 K = 10°C

Recall:

T (K) = T(°C) + 273

T (K) = Temperature in Kelvin

T(°C) = Temperature in decree celcius

Next, we shall convert 100°C to K

T(°C) = 100°C

T (K) = T(°C) + 273

T (K) = 100 + 273

T (K) = 373 K

Thus, 100°C is equivalent to 373 K

Next, we shall convert 373 K to °C

T(K) = 373

T (K) = T(°C) + 273

373 = T(°C) + 273

Collect like terms

373 – 273 = T(°C)

T(°C) = 100°C

Thus, 373 K is equivalent to 100°C

Therefore, option A gives the correct answer.

SUMMARY:

1. Option A. 1 L = 1 dm³

2. Option A. 1 mL = 1 cm³

3. Option B. 0 K = −273 °C

4. Option B. 1000 g = 1 kg

5. Option A. 400 cm = 4.0 m

6. Option B. 1 dm = 0.10 m

7. Option A. 100°C = 373 K

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the answer is 62

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3