1.) You plan to cut a board into 3 pieces to repair part of a railing. You are going to cut the two ends of the board off into two equal pieces that are 1.4 feet long, if the remaining piece needs to be 1.17 times longer than the each of the first two cuts what length board should you buy? Round to the nearest tenth. 2.) You are looking at your power bill for the month, you pay 13 cents per kilowatt-hour. Your power bill came out to $83.96 homes many KWH of energy were used in your house this month?

3.) you were looking at your power bill for the month, you pay nine cents per kilowatt hour. Running a 60 W lightbulb for one hour is .0 6 KWH, if you leave a light on all the time that has 5 lightbulbs in it how much would that cost in a 30 day month? answer in the form of $2.54 without the dollar sign

Here we have 3 general algebraic problems that we need to solve. Using simple reasoning we can solve these.

1) L = 4.4 ft

2) This month you used 645.85 KW-h in your home.

3)Cost =  $19.44

1) You will buy a board of length L.

You will cut two pieces that are 1.4 ft long.

So at this point, the length of the board piece is:

L - 1.4ft - 1.4ft = L - 2.8ft.

Now, you want this to be 1.17 times longer than 1.4ft, then we need to solve:

L - 2.8ft. = 1.17*(1.4ft) = 1.638ft

L = 1.638ft + 2.8ft = 4.438ft

Rounding to the nearest tenth, we get:

L = 4.4 ft

This is the length of board you should buy.

2) Here we know:

You pay $0.13 per KW-h

This month, you pay a total of $83.96

The total number of  KW-h you used is equal to the quotient between the total amount you paid and the price of a single KW-h, this is:

N = $83.96/$0.13  = 645.85

This month you used 645.85 KW-h in your home.

3) Here we know:

You pay $0.09 per KW-h.

Running the bulb for one hour consumes 0.06 KW-h

So, if you leave one of these lights on all day (24 hours) it would consume:

24*0.06 KW-h = 1.44 KW-h

If you instead leave 5 of these bulbs, you will consume 5 times that amount:

5*1.44 KW-h = 7.2 KW-h

This is in one single day, if you do this for 30 days, the total consumption is:

30* 7.2 KW-h = 216 KW-h

And you pay $0.09 for each one of these, then the cost is 216 times $0.09

Cost = 216*$0.09 = $19.44

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