the sum of two resistors in 750 ohms. One is 6.5 times the other. Find the size of each resistor in ohms.

r = 100

6.5r = 650

Step-by-step explanation:

let r be resistors.

6.5r + r = 750

Simplify:

6.5r + r = 750

7.5r = 750

7.5     7.5

   r = 100

100 × 6.5 = 650

One resistor is 100 ohms, and he other is 650 ohms.

Hope this helped.

The sum of two resistors in 750 ohms. One is 6.5 times the other. Find the size of each resistor in ohms.

According to the question, here we need to take a variable to find the size of each resistor then multiply 6.5 with the variable with the first one. For the second there is no change in the variable. Then adding them we get 750 ohms. Simplifying we get their respective size

Let us assume the other resistor's size be x

Here,

The First resistor's size is 6.5 times the other. Hence, the no. is 6.5x

Given that : the sum of two resistors in 750 ohms

FINDING SIZE :

First Resistor's Size = 6.5x = 6.5*100 = 650 ohms

Other Resistor's Size = x = 100 ohms

[Note : Symbol of ohm is Ω]

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet