A path goes around a triangular park, as shown. a. Find the distance around the park to the nearest yard. The distance is about yards. b. A new path and a bridge are constructed from point Q to the midpoint M of PR¯¯¯¯¯¯¯¯ P R ¯ . Find QM Q M to the nearest yard. QM≈ Q M ≈ yd c. A man jogs from P P to Q Q to M M to R R to Q Q and back to P P at an average speed of 150 yards per minute. To the nearest tenth of a minute, about how long does it take him to travel the entire distance?

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

answer: im gonna go with milli

step-by-step explanation: