At a fish farm, at the beginning of the season, the farmer releases a number of fry, which have a mark of 1000. In the fish harvest season, when 120 fish were randomly tested, they had an average weight of 1.6 kg, standard deviation was 0.21 kg, of which 15 were marked. With 95% confidence. a. Estimate the average weight of the total fish in the farm.
b. Estimate the range for the percentage of marked fish in the farm.
c. From sentence b, infer the number of fish in the range?
d. Assume the selling price of fish is VND 27,000/kg, and from the above sentences, calculate the farm's revenue from selling all the fish.
Please help me solve this !!!

step-by-step explanation:

why? because i noticed a pattern. 60 120. those numbers without the zero, make the 6 times tables leaving your answer to be b since 6 times 4 is 24 and adding a zero making it 240.

what am i looking for finish the question.

step-by-step explanation:

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²